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Copy pathMCMC_random_walk.py
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49 lines (43 loc) · 1.18 KB
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#!/usr/bin/python3
## file: MonteCarlo.py
import numpy as np
from numpy import random as nprd
##设定参数
M =10000
pai=lambda x: np.exp(-90*(x[0]-0.5)**2-45*(x[1]+0.1)**2)
domain=lambda x:(x[0]>=-1)*(x[1]>=-1)*(x[0]<=1)*(x[1]<=1)
h=lambda x: domain(x)
h2=lambda x: np.sin(10*x[0])**2+np.log(abs(1+x[1]*10))
#从均匀分布中采样
def sample_q(x):
return (x[0]+0.2*nprd.normal(),x[1]+0.2*nprd.normal())
##独立的MCMC算法,输入:
## N_samples : 抽样次数
## pai(x) : 目标密度函数
## q_sampler(x): 给定x,从q中抽样的函数
## x0 : 初始值
def MH_RW(N_samples, pai, q_sampler, x0):
X=[]
x=x0
for i in range(N_samples):
y=q_sampler(x)
rho=min(1,pai(y)/pai(x))
if nprd.uniform()<rho:
X.append(y)
x=y
else:
X.append(x)
return X
## 计算积分
x=MH_RW(M, pai, sample_q, (0,0))
## 第一个积分
H=list(map(h,x))
## 取h后面80%的样本
subH=H[int(M*0.2):]
integral=np.pi/(90*np.sqrt(2))*np.mean(subH)
print("Intgral1=",integral)
## 第二个积分
H2=list(map(h2,x))
subH2=H2[int(M*0.2):]
integral2=np.pi/(90*np.sqrt(2))*np.mean(subH2)
print("Intgral2=",integral2)