From cd1a1f458f8a761ef561ee35c31bf44d1bc645da Mon Sep 17 00:00:00 2001
From: Alexander Turk <alexmyclo90@gmail.com>
Date: Sun, 4 Mar 2018 03:02:21 -0500
Subject: [PATCH] wipxsdo

---
 arrays.js     | 53 +++++++++++++++++++++++++++++++++++++++++++++++++++
 src/arrays.js | 11 +++++++----
 2 files changed, 60 insertions(+), 4 deletions(-)
 create mode 100644 arrays.js

diff --git a/arrays.js b/arrays.js
new file mode 100644
index 0000000..732a8c2
--- /dev/null
+++ b/arrays.js
@@ -0,0 +1,53 @@
+// Complete the following functions.
+// These functions only need to work with arrays.
+// Do NOT use the built in array methods to solve these. forEach, map, reduce, filter, includes, etc.
+// You CAN use concat, push, pop, etc. but do not use the exact method that you are replicating
+// You can use the functions that you have already written to help solve the other problems
+
+const each = (elements, cb) => {
+for (let i = 0, i < elements.length, i++) {
+  cb(elements[i], i)
+}
+}
+  // Iterates over a list of elements, yielding each in turn to the `cb` function.
+  // This only needs to work with arrays.
+  // based off http://underscorejs.org/#each
+};
+
+const map = (elements, cb) => {
+  for (let i = 0; i < elements.length; i++) {
+      cb(elements[i], i);
+      }
+const reduce = (elements, cb, memo = elements.shift()) => {
+  // Combine all elements into a single value going from left to right.
+  // Elements will be passed one by one into `cb`.
+  // `memo` is the starting value.  If `memo` is undefined then make `elements[0]` the initial value.
+};
+
+const find = (elements, cb) => {
+  // Look through each value in `elements` and pass each element to `cb`.
+  // If `cb` returns `true` then return that element.
+  // Return `undefined` if no elements pass the truth test.
+};
+
+const filter = (elements, cb) => {
+  // Similar to `find` but you will return an array of all elements that passed the truth test
+  // Return an empty array if no elements pass the truth test
+};
+
+/* Extra Credit */
+const flatten = (elements) => {
+  // Flattens a nested array (the nesting can be to any depth).
+  // Example: flatten([1, [2], [3, [[4]]]]); => [1, 2, 3, 4];
+};
+
+/* eslint-enable no-unused-vars, max-len */
+
+module.exports = {
+  each,
+  map,
+  reduce,
+  find,
+  filter,
+  flatten
+};
diff --git a/src/arrays.js b/src/arrays.js
index b995952..732a8c2 100644
--- a/src/arrays.js
+++ b/src/arrays.js
@@ -5,16 +5,19 @@
 // You can use the functions that you have already written to help solve the other problems
 
 const each = (elements, cb) => {
+for (let i = 0, i < elements.length, i++) {
+  cb(elements[i], i)
+}
+}
   // Iterates over a list of elements, yielding each in turn to the `cb` function.
   // This only needs to work with arrays.
   // based off http://underscorejs.org/#each
 };
 
 const map = (elements, cb) => {
-  // Produces a new array of values by mapping each value in list through a transformation function (iteratee).
-  // Return the new array.
-};
-
+  for (let i = 0; i < elements.length; i++) {
+      cb(elements[i], i);
+      }
 const reduce = (elements, cb, memo = elements.shift()) => {
   // Combine all elements into a single value going from left to right.
   // Elements will be passed one by one into `cb`.