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package Chap3;
/**
* 输入数字n,按顺序打印处1到最大的n位十进制数,比如输入3,则打印1~999之间的数
*/
public class PrintFrom1ToMaxOfNDigit {
public void printFrom1ToMaxOfNDigit(int n) {
if (n <= 0) {
return;
}
StringBuilder sb = new StringBuilder();
for (int i = 0; i < n; i++) {
sb.append("0");
}
while (stillIncrease(sb, n)) {
print(sb);
}
System.out.println();
}
private boolean stillIncrease(StringBuilder sb, int len) {
// 进位,应该要给下一位相加,所以设置在循环外
int toTen = 0;
// 从个位开始加,如果有进位就看十位...如果到最高位还有进位,说明溢出;
for (int i = len - 1; i >= 0; i--) {
// 加上进位toTen
int sum = sb.charAt(i) - '0' + toTen;
// 在个位上,先自增
if (i == len - 1) {
sum++;
}
if (sum == 10) {
// 进位溢出
if (i == 0) {
return false;
// 需要进位,当前位置为0,
} else {
sb.setCharAt(i, '0');
// 进位了
toTen = 1;
}
} else {
sb.setCharAt(i, (char) (sum + '0'));
// 在某位上自增后不再进位,自增完成立即退出循环
break;
}
}
return true;
}
private void print(StringBuilder sb) {
int start = sb.length();
// 找到第一个不为0的索引
for (int i = 0; i < sb.length(); i++) {
if (sb.charAt(i) != '0') {
start = i;
break;
}
}
// 如果全是0,就不会打印
if (start < sb.length()) {
System.out.print(sb.substring(start) + " ");
}
}
public void printFrom1ToMaxOfNDigitRecur(int n) {
if (n <= 0) {
return;
}
StringBuilder sb = new StringBuilder();
for (int i = 0; i < n; i++) {
sb.append("0");
}
printRecur(sb, n, -1);
System.out.println();
}
private void printRecur(StringBuilder sb, int len, int index) {
if (index == len - 1) {
print(sb);
return;
}
for (int i = 0; i < 10; i++) {
// 一定是先设置了字符,然后再递归
sb.setCharAt(index + 1, (char) (i + '0'));
printRecur(sb, len, index + 1);
}
}
public static void main(String[] args) {
PrintFrom1ToMaxOfNDigit a = new PrintFrom1ToMaxOfNDigit();
a.printFrom1ToMaxOfNDigit(2);
a.printFrom1ToMaxOfNDigitRecur(2);
}
}